The figure shows a network of four resistors | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the potential at point $F$ be $V_F = 0\,V$.Applying Kirchhoff's voltage law to the left loop $(ABCF)$:$30 - 4I_1 - 6 - 2I_1 = 0$$24 = 6I_1 \im

Vedclass · Accepted Answer

Only $6\,V$

Vedclass · Answer

(A) Let the potential at point $F$ be $V_F = 0\,V$.Applying Kirchhoff's voltage law to the left loop $(ABCF)$:$30 - 4I_1 - 6 - 2I_1 = 0$$24 = 6I_1 \implies I_1 = 4\,A$.Applying Kirchhoff's voltage law to the right loop $(CDEF)$:$15 - 1I_2 - 6 - 2I_2 = 0$$9 = 3I_2 \implies I_2 = 3\,A$.The total current flowing through the $6\,V$ battery is $I = I_1 + I_2 = 4 + 3 = 7\,A$.Since the current $I$ enters the positive terminal of the $6\,V$ battery,it is getting charged.For the $30\,V$ battery,current $I_1$ leaves the positive terminal (discharging).For the $15\,V$ battery,current $I_2$ leaves the positive terminal (discharging).Therefore,only the $6\,V$ battery is getting charged.

The figure shows a network of four resistors and three batteries. Which of the batteries is getting charged?

Similar Questions

In the arrangement of resistors shown in the diagram,the potential difference between $B$ and $D$ will be zero when the unknown resistance $X$ is ............... $\Omega$.

In the adjoining circuit,the battery $E_1$ has an $e.m.f.$ of $12 \, V$ and zero internal resistance,while the battery $E$ has an $e.m.f.$ of $2 \, V$. If the galvanometer $G$ reads zero,then the value of the resistance $X$ in $\Omega$ is

In the following network,the current through the galvanometer will:

State the principle of a Wheatstone bridge.

As the switch $S$ is closed in the circuit shown in the figure,the current passed through it is .................. $A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module